BANDW

Black and White

Link to the question : BANDW 

HINT :

My solution is very basic.Let the input string be s[] and the objestive string be t[].  Run a loop till the end. If s[i] = t[i] continue, else if they are not equal, keep a count again when they are equal.

I think checking the source code once will make it more clear.

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SOURCE CODE :

/* Black And White */

/* Sushant Gupta */



#include<stdio.h>

#include<string.h>

int main()

{

    char s[600],t[600];

    int i;

    s[0]= '0';



    while(s[0]!= '*')

    {

        scanf("%s%s",s,t);

        if(s[0]!= '*')

        {

            int n,c=0;

            n = strlen(s);

            i=0;

            while(i<n)

            {

                if(s[i]!=t[i]) {

                while(s[i]!=t[i])

                    i++;

                c++;}

                while(s[i]==t[i])

                    i++;

            }

            printf("%d\n",c);

        }

        else

            return 0;

    }

}