Friday, 11 September 2015

YELBRICK

Standard


The Yellow Brick Road

Link to the question : YELBRICK 

HINTS :

Very simple ad-hoc question. Just find the gcd of the length, breadth and height of the stones, and then find the number of stones that can be produced.

RECOMMENDED  QUESTION :

Try solving this question as even this requires some application of gcd.

SOURCE CODE :

#include <iostream>
using namespace std;
int gcd(int x,int y)
{
    while(x!=y){
          if(x>y)
              return gcd(x-y,y);
          else
             return gcd(x,y-x);
     }
     return x;
}
int main() 
{
    int n,i;
    while(1)
    {
        cin>>n;
        if(n==0)
        break;
        int a[n][3];
        long long vol=0;
        for(i=0;i<n;i++)
        {
            cin>>a[i][0]>>a[i][1]>>a[i][2];
        }
        int hcf =a[0][0];
        for(i=0;i<n;i++)
        {
            hcf = gcd(hcf,a[i][0]);
            hcf = gcd(hcf,a[i][1]);
            hcf = gcd(hcf,a[i][2]);
        }
        for(i=0;i<n;i++)
        {
            vol+=(long long)((a[i][0]/hcf)*(a[i][1]/hcf)*(a[i][2]/hcf));
        }
        cout<<vol<<"\n";
    }
    return 0;
}

2 comments:

  1. Sir can you tell me the meaning of ad-hoc ? Very nice solution sir :)

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