Factorial length
Link to the question : LENGFACT
HINT :
Apply the kamenetsky formula.
SOURCE CODE :
#include<stdio.h>
#include<math.h>
int main()
{
int t;
long long int ans,n;
scanf("%d",&t);
while(t--)
{
ans=0;
scanf("%lld",&n);
if(n<3)
printf("1\n");
else{
ans=ceil(log10(2*3.141592653589793*n)/2 + n*log10(n/2.7182818284590452353));
printf("%lld\n",ans);
}
}
return 0;
}
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